Related Resources: mechanics machines
Flywheel Mass Size Design Equation and Calculator
Preview: Flywheel Mass, Size Design Calculator
The torqueangle relationship for an engine or machine depends on the the amount of work required. The large variation that is possible between different machine designs shows that dynamic measurement or kinematic analysis is necessary to determine the torque fluctuation. It is often necessary, however, to come up with a rough estimate for preliminary design purposes or for checking the reasonableness of calculated values. For these purposes, the energy variation for a machine or internalcombustion engine can be estimated by:
Energy equation variation flywheel
U = 0.5 J ( ω^{2}_{max}  ω^{2}_{min} )
Polarmass moment of inertia Fly Wheel. This inertia includes the flywheel inertia and the inertia of all rotating parts, referred to the flywheel speed by multiplying by the square of the ratio of the shaft speeds.
J = U / ( ω^{2}_{avg} C_{s} )
Coefficient of Speed Variation of a Flywheel
C_{s} = ( ω_{max}  ω_{min} ) / ω_{avg}
Suggested Design Values for the Coefficient of Speed Fluctuation C_{s}
Required speed uniformity 
C_{s}

Very uniform 
≤ 0.003

Moderately uniform 
0.0030.012

Some variation acceptable 
0.0120.05

Moderate variation 
0.050.2

Large variation acceptable 
≥ 0.2

The coefficient of energy variation C_{u} can be approximated for a twostroke engine with from 1 to 8 cylinders using the equation:
C_{u} = 7.46 / ( N_{c} + 1 )^{3}
Coefficient of energy variation for a fourstroke engine with from 1 to 16 cylinders using the twobranched equation:
C_{u} = 0.8 / ( N_{c}  1.4 )^{1.3}  0.015
Flywheel Weight:
W = J g / r^{2}_{a}
Cross Sectional Area of Flywheel:
A = J g / ( 2 π ρ r^{3}_{a} )
Power required :
P = T ω
Where:
J = Polarmass moment of inertia, Ib · s^{2} · ft (N · s^{2} · m)
U = Energy Variation, difference between the flywheel energy at maximum speed and at minimum speed, Ib · ft (J)
N_{c} = Number of cylinders
C_{u} = Coefficient of energy variation
C_{s} = Uniformity Speed Constant
K = 33 000 lb · ft · rpm/hp
ω = Rotational speed, rad/s
ω_{avg} = Average of ω_{max} and ω_{min} , rad/s
P = Power, hp (W)
g = Gravity 9.81 m/s^{2}
D = Diameter m
r_{a} = radius m
W = Mass kN
A = Cross sectional Area m^{2}
ρ = Material Density kg/m^{3}
T = Torque J ( 1 ftlb = 1.355817948 J)
Typical Machine Power Cycle