Related Resources: heatlossinsulatedpipe

Heat Loss Insulated Pipe Equation and Calculator

Heat Transfer Engineering

Equations and calculator to determine the conductive heat loss through a cylinder with multiple layers that may include a pipe wall insulation.

The temperature gradient within a homogeneous material results in an energy transfer rate within the medium which can be calculated with the following equation

Heat Loss equation eq. a

Insulated Pipe

The illustration above depicts a single-layer cylindrical wall of a homogeneous material with constant thermal conductivity and uniform inner and outer surface temperatures. At a given radius the area normal to radial heat flow by conduction is 2 Π r L, where L is the cylinder length. Substituting this into (eq. a) and integrating with q constant gives:

Delta tempaeratureeq. 0


Heat loass equation eq. 1

Multi Layer Pipe

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From (eq 1) the thermal resistance of the single cylindrical layer is [ ln (r2 / r1) ] / 2rkL. For a two-layered cylinder show below the heat transfer rate is,

Conductive Heat Flow = Overall Temperature Difference / Summation of Thermal Resistance's

Heat loss divided by length eq 2


Heat loss eq 3


k = thermal conductivity (Btu / h · in· °F)
ka = thermal conductivity inner wall (Btu / h · in· °F)
ka = thermal conductivity outer wall (Btu / h · in · °F)
L = length of cylinder and insulation layer (in)
q = conduction (Btu / h · °F)

The following is the original (pre-7/2016) equations and calculator:

ΔT = (TsEst - Ta)

hs = ΔT - Ds + ΔT2 + Ds2 - ΔT Ds