Related Resources: concrete beam shear

Concrete Rectangular Beam Section Analysis Calculator

Concrete Rectangular Beam Section Analysis Calculator Beam or One-Way Type Shear per Per ACI 318-05 Code

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 RECTANGULAR CONCRETE BEAM/SECTION ANALYSIS Beam or One-Way Type Shear Per ACI 318-05 Code Input Data: Beam or Slab Section? BeamSlab Reinforcing Yield Strength, fy = ksi Concrete Comp. Strength, f 'c = ksi. in. Depth to Tension Reinforcing, d = in. in. Ultimate Design Shear, Vu = kips Ultimate Design Axial Load, Pu = kips Total Stirrup Area, Av(used) = in.^2 Tie/Stirrup Spacing, s = in. Results: fVc = The ultimate shear strength provided by the concrete, 'fVc', is calculated as follows: For shear and flexure only (no axial load): fVc = 2*f*(f'c*1000)^(1/2)*b*d For shear with axial compression: fVc = 2*f*(1+Pu/(2*Ag)*(f'c*1000)^(1/2)*b*d For shear with axial tension: fVc = 2*f*(1+Pu/(0.5*Ag)*(f'c*1000)^(1/2)*b*d where: f = 0.75 Ag = b*h Note: for members such as one-way slabs, footings, and walls, where minimum shear reinforcing is not required, if fVc >= Vu then the section is considered adequate. For beams, when Vu > fVc/2 , then a minimum area of shear reinforcement is required. fVs = The ultimate shear strength provided by the shear reinforcing in beams, 'fVs', is calculated as follows: fVs = f*fy*d*Av/s2 where: f = 0.75 The required amount of shear strength to be provided by the shear reinforcing in beams is: fVs(req'd) = Vu-fVc >= 0. The required amount of shear strength to be provided must be <= fVs(max). kips fVn = fVc+fVs = fVs(max) = The maximum allowable ultimate shear strength to be provided by the shear reinforcing in beams, 'fVs(max)', is calculated as follows: fVs(max) <= 8*f*(f'c*1000)^(1/2)*b*d/1000 where: f = 0.75 Av(prov) = in.^2  = Av(used) Av(req'd) = The required area of shear reinforcing, 'Av', perpendicular to axis of the beam is calculated as follows: Av = fVs*s/(f*fy*d) >= Av(min) where: f = 0.75 fVs = max. of: (Vu - fVc) or 0 Note: Av = area of both legs of a closed stirrup. Av(min) = The minimum area of shear reinforcing, 'Av(min)', to be provided for beams is calculated as follows: Av(min) = 75*SQRT(f'c*1000)*b*s/fy but not less than: 50*b*s/(fy*1000) Note: Av(min) = area of both legs of a closed stirrup. s(max) = The maximum allowable shear reinforcing (closed stirrup) spacing, 's', shall not exceed d/2, nor 24". However, when fVs > 4*f*(f'c*1000)^(1/2)*b*d, then the maximum spacing given above shall be reduced by one-half. (Note: f = 0.75)